How do you solve log x 3?

Log(sub2)x+log(sub2)[x-2]=3… How do you solve that?

Answer #1

thanks…genius!

Answer #2

log(base2)(x) + log(base2)(x-2) = 3

Combine the Logs:

log(base2)(x(x-2)) = 3

Raise both sides over 2 (the base):

x(x-2) = 2^3 = 8

Put it together:

x^2 - 2x - 8 = 0

Factorise:

(x+2)(x-4) = 0

Therefore:

x = -2, or +4.

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