Science equations

ok, so you’re trying to make the same number of atoms on the right as on the left…

now the only rule here is that you have to add the number before the equation, because adding it afterwards changes the compound… (this would be easier to show you if I could draw it, but just take my word for it).

So…

H2 + O2 = H2O

so there’s two Hs on the left and two on the right, so that’s fine Now there’s two Os on the left, and only one on the right, so we add two on the right…

H2 + O2 = 2H2O

Ok, so lets see if that balances out. Now we’ve got two Hs on the left, but 4 Hs on the right (2 x 2 = 4), so, we fix that…

2H2 + 1O2 = 2H2O

ok, now we’ve got 4 Hydrogen atoms on the left, 4 on the right we’ve got 2 oxygen atoms on the left, 2 on the right, so we have a balanced equation…

Fe + Cl2 = FeCl3

ok so we’ve got 1 Fe on left, one Fe on right, so far so good now we’ve got 2 Cl on the left, and 3 on the right… Now we have to make them equal by multiplying them by a number… so if we make them both 6 they should be equal… so (3 x2 = 6)

Fe + 3Cl2 = 2FeCl3

Now we’ve got 6 clorine atoms on both sides. But we’ve got 1 Fe on the left, and 2 on the right, so we fix that

2Fe + 3Cl2 = 2FeCl3

Now we check. 2 Fe on left, 2 Fe on right, 6 Cl on left, 6 Cl on right

Cu + AgNO3 = Cu(NO3)2 + Ag

so 1 Cu on left, 1 on right 1 Ag on left, 1 on right 1 and on left, 2 on right so lets fix that

Cu + 2AgNO3 = Cu(NO3)2 + Ag

so 1 Cu on left, 1 on right 2 Ag on left, 1 on right

so we fix that

Cu + 2AgNO3 = Cu(NO3)2 + 2Ag

so 1 Cu on left, 1 on right 2 Ag on left, 2 on right 2 and on left, 2 and on right 6 O on left, 6 O on right

etc etc