How do you prove the distance formula for two points on the Cartesian plain?

and to prove it you have to plug in the coordinates if l.s=’s r.s then it is proved

I like the way you said it, but i’m afraid he will not understand.

LOL….LOL…LOL…to Juar!

Umm yea I didn’t get it…umm but from what I remember we needed to start off with the two points and turn it into the actual distance formula that you first showed. So you needed to start with the two points then find the third point to complete a triangle that point would be(x2,y1) then you would have two sides then to find the distance between the two original points you would use the Pythagorean theorem and that’s all I remember…pretty sure we are talking about two different proofs.

You are given two points: (X1,Y1) (X2,Y2). for example: (4,3) (2,1) <–– those would be the points you are solving with The formula is distance=√(x2-x1)^2 + (y2-y1)^2 √ is the square root symbol ^2 means “to the power of 2”

First, you do what’s in the parenthesis. Next, square both numbers (raise them to the power of 2) Then, add those two numbers together. Finally, find the square root of whatever number you get from the last step.

That is the distance formula I have to prove it by starting with two points and turning it into the distance formula…it’s hard to explain