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Math help please I need it, thnxxx. It might be easy 4 you. :)
The sum of 9 consecutive whole numbers is 123,456,789,987,654,321. What is the difference between the largest and the smallest of these numbers?
its 8 , kusari gave you the equation that helps
They’re all consecutive whole numbers. If you let n = the first whole number, then your last number (the 9th number) would be equal to n + 8.
Difference between last and first number = (n + 8)  n
= 8
Very easy problem lol.
the answer is 864. because the largest number is 987 and the smallest number is 123 and they ask the difference of them, so you subtract 987 from123 and you get 864!
To figure it out, divide 123,456,789,987,654,321 by 9.
You get 13,717,421,109,739,369
To find out the nine consecutive numbers, simply change the last three digits (369) eight times. Four above 369 and four below so you will repeat the answer nine times as follows:
13,717,421,109,739,373 13,717,421,109,739,372 13,717,421,109,739,371 13,717,421,109,739,370 13,717,421,109,739,369 13,717,421,109,739,368 13,717,421,109,739,367 13,717,421,109,739,366 13,717,421,109,739,365
Those are your nine consecutive numbers, so 13,717,421,109,739,373 (the largest) minus 13,717,421,109,739,365 (the smallest) is 8 (the difference).

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