How to solve a right triangle when you know all the angles and the hypotenuse?

Your formula is, for the reasons specified by filletofspam:

sin(63)6.7 = X

Interesting! We were taught SOH CAH TOA… . Sine = Opposite ÷ Hypotenuse

Cosine = Adjacent ÷ Hypotenuse

Tangent = Opposite ÷ Adjacent

It’s weird how some things never ever leave your brain even though you use them for nothing, once you’ve completed the final exam! No wonder I can never find my car keys. My brain is full of mnemonics.

Your comment actually got me to look at what I wrote and I realized that I put the wrong mnemonic down. Considering that I spent a few years working on discrete cosine transforms you’d think I would get the basic functions correct!

The mnemonic for sin, cos, and tan should be “Oscar Had A Heap Of Apples”

The mnemonic I put above was for for cosecant, secant, cotangent which are 1/sin, 1/cos, 1/tan respectively. Considering that these are reciprocals of the other functions they probably do not really require a seperate mneumonic past remembering to flip the numerator and operator. I’m suffering from mnemonic overload I guess.

Sorry for any confusion; especially if it resulted in an incorrect homework answer!

Mnemonics are actually the easiest way to learn. They trick the brain into indexing the same information multiple ways for easier retrieval.

Oops! Its cos(63)6.7 = X

Because another triangle could have exactly the same angles, but its sides could all be twice as long, or 62 times as long etc.

There are an infinite number of triangles that all have the same two acute angles. They’re all similar to each other, but they’re not congruent.

http://funadvice.com/r/15dmnodmqcj